The Chemistry of Hydrogen
Chemical Concepts Demonstrated: Chemistry of hydrogen, activation energy
Demonstration:
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Observations:
The helium balloon pops. The H2 balloon explodes into a cloud of flame. The balloon with the mixture of H2 and O2 produces a very large explosion.
Explanations:
Helium is an “inert” gas and does not react in the presences of heat or air. This is why the balloon filled with helium does nothing more than pop.
Hydrogen gas is very flammable. This is why the balloon filled with hydrogen ignites.
The heat given off by the candle provides the activation energy required for the reaction that produces water from hydrogen and oxygen. This reaction is highly exothermic, producing the prodigious explosion. It should be noted that, if this reaction were carried out with the stoichiometric ratios for a complete reaction (i.e. two parts hydrogen for each part oxygen), the resulting explosion would be larger, but would also be too dangerous to be used as lecture demonstration.
Thermodynamically, the reaction between hydrogen and oxygen is very favorable. However, a balloon filled with hydrogen and oxygen at room temperature will remain inert indefinitely. Kinetically, one must apply an energy of some kind in order to get the reaction started. Once the candle provides this activation energy, the balloon’s chemicals react, and the balloon detonates.
The Chemistry of Oxygen
Chemical Concept Demonstrated: Chemistry of oxygen
Demonstration:
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Observations:
The Mg ribbon ignites and burns with a bright white flame.
Explanation:
2 Mg (s) + O2 (g) —> 2 MgO (s)
Mg (s) + N2 (g) —> Mg3N2 (s) (The Mg ribbon reacts with both the oxygen and the nitrogen in the air.)
Oxygen is highly electronegative. It acts as an oxidizing agent for most substances with which it reacts. The oxygen oxidizes the magnesium ribbon to form the magnesium oxide salt.
The fact that the magnesium also undergoes oxidation with respect to nitrogen only attests to the magnesium’s reactivity, not to any property of oxygen.
When the salts produced in this demonstration are placed in water, a basic solution is formed
Plastic Sulfur
Chemical Concepts Demonstrated: Sulfur chemistry, polymers
Demonstration:
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Observations:
The newly solidified sulfur (now ropelike) is capable of stretching and bending.
Explanation:
Sulfur in its yellow, powdery form is an octahedral ring. Heat breaks up this ring. When the molten sulfur is cooled by immersion into water, it forms a series of covalent bonds, or chains, much like a carbon polymer. This chain structure is one of the primary reasons why polymers have the physical properties that they do. It is interesting to note that the ability of sulfur to form carbonlike chains is critical to the process of vulcanizing rubber.
Oxides of Nitrogen
Chemical Concepts Demonstrated: Nitrogen chemistry, enthalpy, dimerization
Demonstration:
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Observations:
The tube filled with NO2 will produce a white solid, while the the tube with the mixture of NO and NO2 will produce a blue liquid.
Explanations:
The white solid is N2O4. The blue liquid is N2O3. The products are different because of various factors, including the available starting materials.
Based on the observation that N2O4 is not produced in the tube containing both NO and NO2, it can be inferred that N2O3 is a more favorable product than N2O4 under these conditions. In fact, the production of N2O3 from NO and NO2 has an overall enthalpy change of only 39.71 kJ/mol, while the production of the dimer (from the Greek, “two parts”) N2O4 from two NO2 molecules has an enthalpy change of 57.20 kJ/mol. The more negative an enthalpy of a reaction is, the easier it is to perform the reaction (thermodynamically). In addition to this, any small quantities of N2O4 and N2O2 produced would be almost invisible (N2O4 is white and N2O2 is colorless).
Mock Sun
Chemical Concept Demonstrated: Chemistry of phosphorus
Demonstration:
| A flask is filled with O2, and phosphorus is ignited and immersed in the flask (picture #2). | ![]() |
Observations:
The phosphorus lights up brightly. As the flask fills with smoke, the entire flask gives off a uniform glow.
Explanation:
Phosphorus reacts with oxygen in an exothermic reaction:
P4 (s) + O2 (g) –> P4O10 (s)
This reaction produces so much light that it is nicknamed the “Mock Sun.”
The Chemistry of the Halogens
Chemical Concepts Demonstrated: Oxidation/reduction chemistry of halogens and their halides, relative strengths of oxidizing and reducing agents
Demonstration:
Prepare three solutions each of NaI (aq), NaBr (aq), and NaI (aq).
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Observations:
The halogen has been extracted into the bottom organic phase.
1. The metallic color of iodine can be seen in both tubes in the first set of reactions.
2. The reddish color of bromine can be seen in the first test tube but not in the second.
3. The yellow color of chlorine can NOT be seen in either of the test tubes.
4. Only iodine has been extracted from the halide solutions reacted with Fe3+.
Explanations (including important chemical equations):
1. Cl2(aq) + 2 NaI(aq) —> 2 NaCl (aq) + I2(aq)
Br2(aq) + 2 NaI(aq) —>2 NaBr(aq) + I2(aq)
2. Cl2(aq) + 2 NaBr(aq) —> 2 NaCl (aq) + Br2(aq)
I2(aq) + 2 NaBr(aq) —> 2 NaI(aq) + Br2(aq)
3. Br2(aq) + 2 NaCl(aq) —>2 NaBr(aq) + Cl2(aq)
I2(aq) + 2 NaCl(aq) —> 2 NaI(aq) + Cl2(aq)
4. Fe3+ (aq) + NaI (aq) —> Fe2+ (aq) + I2(aq)
X2 (aq) + 2 Y (aq) —> 2 X (aq) + Y2 (aq)
X2 must be a stronger oxidizing agent than Y2, and Y must be a stronger reducing agent than X in order for the reactions to occur.
Cl2 is a stronger oxidizing agent than Br2. Br2 is a stronger oxidizing agent than I2. ( Cl2 > Br2> I2)
I– is a better reducing agent than Br –. Br – is a better reducing agent than Cl–. (I–> Br –> Cl–)
Fe3+ is a stronger oxidizing agent than I2, but not as strong as Br2. ( Cl2 > Br2> Fe3+ >I2)
Free-Radical Reactions–The H2/Cl2 Reaction
Chemical Concepts Demonstrated: Free-radical reaction mechanisms, photochemical reactions
Demonstration:
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Observations:
Nothing happens when the black cloth is removed. Once the “picture” is taken, the gases within the tube react.
Explanation (including important chemical equations):
The UV radiation from the flash initiated the reaction between the H2 and Cl2 gas. The reaction proceeds via a chain-reaction mechanism.
overall reaction: H2 + Cl2 —> 2 HCl
initiation: Cl2 + hv —> 2 Cl �
propagation: Cl � + H2 —> HCl + H�
H� + Cl2 —> HCl + Cl �
termination: 2 H� —> H2
2 Cl � —> Cl2
H� + Cl � —> HCl
The enthalpy for the overall reaction is -184.6 kJ per two moles of HCl. However, the enthalpy for the initial step is 243.36 kJ per mole of Cl2. This corresponds to the energy carried by photons with a wavelength of 491.5 nm This reaction is catalyzed by light toward the violet end of the visible spectrum.
It should be noted that, because a camera’s flash bulb initiates the reaction, a certain amount of showmanship could be employed. For example, one could take the cloth off and, when nothing happens, take a photograph of the demonstration under the ruse that it actually failed and such a picture is a necessary bit of documentation in such an event.
The Catalytic Decomposition of Hydrogen Peroxide
Chemical Concepts Demonstrated: Chemisty of hydrogen peroxide, disproportation reactions, enzyme catalysis
Demonstration:
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Observations:
The various items foam in the dishes.
Explanation (including important chemical equations):
Hydrogen peroxide undergoes disproportionation. Both oxidation and reduction occur at the same time.
2 H2O2 (aq) —> 2 H2O (l) + O2 (g) enthalpy: -196.1 kJ/mol
The activation energy of the reaction is about 75 kJ/mol in the absence of catalyst. Platinum metal catalysts can lower the activation energy to about 49 kJ/mol. The catalase enzyme (found in blood) lowers the activation energy to below 8 kJ/mol, which corresponds to an increase in the rate of reaction at physiologial temperatures by a factor of 2 x 10 11 or more.
The Catalytic Decomposition of Hydrogen Peroxide, II
Chemical Concept Demonstrated: Catalysis
Demonstration:
Observations: As soon as the catalyst is added, an eruption of foam flies out of the top of the gas column. Explanation (including important chemical equations): This demonstration is based on the decomposition of hydrogen peroxide into water and oxygen gas. Reactions like these that are both oxidations and reductions are known as disproportionation reactions: 2 H2O2(aq) -> 2 H2O(l) + O2(g) Left on its own at room temperature, this reaction happens at a rate so slow that, for practical purposes, it may as well not even exist. A catalyst is added to speed things along. The KI added dissociates into K+ and I–, at which point the I– begins its work. The reaction pathway represented below has a lower activation energy than the straight decomposition represented above: H2O2(aq) + I–(aq) -> OI–(aq) + H2O(l) H2O2(aq) + OI–(aq) -> H2O(l) + O2(g) + I–(aq) Note that the iodide ion is conserved in this reaction (it is not consumed in the sum of the reactions, and the same iodide ion could potentially go through many such cycles). This is the definition of a catalyst: a substance that increases the rate of a chemical reaction without being consumed in the reaction.
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